The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 -2/5 = (x – 10). What is the standard form of the equation for this line?
A. 2x – 5y = –15
B. 2x – 5y = –17
C. 2x + 5y = –15
D. 2x + 5y = –17

Question

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 -2/5 = (x – 10). What is the standard form of the equation for this line?
A. 2x – 5y = –15
B. 2x – 5y = –17
C. 2x + 5y = –15
D. 2x + 5y = –17

dayakar · Answer

equation u written is wrong plz check a small correction is needed

faiqraees · Answer

C is the correct answer. 
Just take any point like (10,-7) and plug it into every equation. If the equation is correct, the right-hand side and the left-hand side of the equation will be equal.
For C
2x+5y=-15
X=10 y=-7
2(10)+5(-7)=-15
20-35=-15
-15=-15