Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Vectors on a plane please help!?

OpenStudy (anonymous):

Let u = <-5, -9>, v = <6, 8>. Find -8u - 2v. <52, 88> <-8, 2> <112, -28> <28, 56> Let u = <-7, -2>. Find 8u. <56, 16> <-56, 16> <-56, -16> <56, -16>

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

Hey!

OpenStudy (anonymous):

Ok the page finally loaded

OpenStudy (anonymous):

I'm not sure why it takes so long to load

OpenStudy (anonymous):

Are you still here?

OpenStudy (anonymous):

The lesson does not explain this well, is there a formula or something I can use?

ganeshie8 (ganeshie8):

Let u = <-7, -2>. Find 8u.

ganeshie8 (ganeshie8):

multiply each component of \(u\) by 8

ganeshie8 (ganeshie8):

u = <-7, -2> 8u = <-7*8, -2*8> = ?

OpenStudy (anonymous):

-56, -16?

ganeshie8 (ganeshie8):

<-56, -16>

OpenStudy (anonymous):

That's easier than it looks.

ganeshie8 (ganeshie8):

Can you try the first problem ?

ganeshie8 (ganeshie8):

Let u = <-5, -9>, v = <6, 8>. Find -8u - 2v. -8u = ? -2v = ?

OpenStudy (anonymous):

I will -8u = -5*-8, -9*8 = 40, 78 -8u = 6*-8, 8*-8 = -48, -64 Is this right so far?

OpenStudy (anonymous):

-2v = -5*-2, -9*-2 = 10, 18 -2v = 6*-2, 8*-2 = -12, -16

OpenStudy (anonymous):

I feel like I ended up with too many numbers

ganeshie8 (ganeshie8):

Just find -8u and -2v

ganeshie8 (ganeshie8):

u = <-5, -9> -8u = ?

OpenStudy (anonymous):

-5*-8 = 40, -9*-8 =72

ganeshie8 (ganeshie8):

u = <-5, -9> -8u = <40, 72>

ganeshie8 (ganeshie8):

v = <6, 8> -2v = ?

OpenStudy (anonymous):

So <40,72> And then 6*-2 = -12, 8*-2 = -16 So <-12,-16>

ganeshie8 (ganeshie8):

Yes, add them both : -8u - 2v = -8u + -2v = <40, 72> + <-12,-16> = ?

OpenStudy (anonymous):

40 - (-12) = 52 72 - (-16) = 88 <52,88>

OpenStudy (anonymous):

Oh so <28, 56> Why add

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!