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Physics 15 Online
OpenStudy (anonymous):

A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is the minimum force needed to set the box in motion across the floor? -49 N -31 N -62 N -119 N

OpenStudy (tinyclown):

f=-kx... f= -(.42)(12*9.8)..12 has to be multiplied by 9.8 to convert kilograms to newtons which is what force is measured in..which is -49.392 N...

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