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please help.. find limit as thete approaches 0 of cos(6theta)tan(6theta)/theta
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\[ \dfrac{cos(6\theta)tan(6\theta)}{\theta}\] that's \[ \dfrac{sin(6\theta)}{\theta}\] !!!!!!!!!!!!
Just to add the last hit to what IrishBoy did, \(\color{#000000 }{ \displaystyle \lim_{\theta \to 0}\frac{\sin(6\theta)}{\theta}\quad \Longrightarrow \quad 6\cdot \lim_{\theta \to 0}\frac{\sin(6\theta)}{6\theta} }\)
but, I think that without that it's pretty obvious.
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