Question

State the domain and range of this square root function:y=3(sqrtx+2)+1 graphic. Then describe the transformations that you would do to get to the parent function.

Answer 1

There are serious problems in your expression " y = 3(sqrtx+2)+1."

Exactly what do you mean by "(sqrtx+2)" ? Which quantity is the "argument" of the sqrt function?

Please re-write your question.

Answer 2

it is written exactly how i need it to be
plus its the way its written on my paper

Answer 3

y= 3(sqrt x +2) +1

Answer 4

domain \[x \geq 0\]

Answer 5

when x=0
y=3(0+2)+1=7
range \[\geq 7\]