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how do i find the interior angle sum of a polygon?
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(n-2)*180
Where n is number of sides.
thanks
yw ;)
:)
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this time it gives me the angle sum. would i do n+2 X 180
Sum=(n-2)*180 Solve for n.
how?
(n-2)*180 where n is number of side for triangle n=3 side so sum of angle=(3-2)*180=1*180=180
Just rearrange the equation for n.
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so 180* 2+n?
ill just put the question in
Nope you need to separate n alone and take all other terms to the other side.
so n-2*180 +2 +2 n* 180 +2 ??
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