Ive been stuck for hours.. Please help..? f(x)=2-2x Evaluate f(4) a 14 b -10 c -5 d 12 Which ordered pair is the turning point of the graph of f(x)=|x-4| a 4,0 b 0,4 c 0,-4 d -4,0
I can help. Fornstarters though I'd like you tocheck the function - are u sure it is 2-2x, and not -2-2x?
Oops it shouldnt be 2-2x it should be 2-3x.. i thought i fixed that
input 4 into x
i think you can continue from here
Ok that makes more sense . Now one ofnthe four answers is possible.
Do you knowhow to go about the second part?
No, i do online schooling, and its a brand new teacher at teaching, and she barely went over the topic. & in our course there isnt much reading. :/ All it we really do is just quizzes after quizzes.. little time with the teacher
|x-4| actually means -x+4=0
Hmm I think it is not D. But I'd prefer if we came up with the solution together.
i think you can take it from here
i already got the solution on there
x=4
(x,y) Now what do u think the answer is if Y=0
Would you be able to draw the graph of the function |x-4|
i did that on my phone I think i actually just got the answer.. Would it be -10
If you are still with the first part then yes it is -10.
Am correct it is A
for the second solution
1.B 2.A
I need to be absolutely sure of this: Does your "f(x)=2-2x" represent a linear function of the form y=mx+b, or did you mean "exponentiation," as in \[f(x)=2-2^x?\]
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