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Which equation of a line is perpendicular to the given line and passes through (-2, 3) y - 3 = 8/3(x +2)
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The above equation is y = 8/3x + 25/3. Since it's slope is 8/3, the slope for the perpendicular line will be -3/8.
Is the correct answer y - 3 = -3/8(x + 2) OR y -2 = -3/8(x + 3)
@imqwerty @jhonyy9 @mathmale @nincompoop
i'm alittle confused on this!
y-3= 8/3(x+2) y= 8/3(x+2) +3 y = (8x+16 +9)/3 y = (8x +25)/3 y = 8x/3 +25/3
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