Question

I would like to know how to rewrite this expression with common logarithms with log base 2 to the 10

Answer 1

use the change of base formula

\[\log_ba=\frac{\log_ca}{\log_cb}\]

Answer 2

i.e.
\[\log x = \log_{10}x=\frac{\log_2x}{\log_210}=\frac{\operatorname{lb}x}{\operatorname{lb}10}\]or
\[\ln x = \log_ex=\frac{\log_2x}{\log_2e}=\frac{\operatorname{lb}x}{\operatorname{lb}e}\]

Answer 3

thank you very much

Answer 4

\[\ddot\smile \]