Question

X+1/x-2 how to find the range of it?

Answer 1

range means value of function when put the different value of x

Answer 2

what is 3/0? @Zaada ?

Answer 3

No defined :)

Answer 4

good..its not defined..So the denominator can never be zero..right?

Answer 5

then what value should x not take..so that x-2 is not equal to 0

Answer 6

2

Answer 7

great job!

Answer 8

But, is not that how we find the domain of the function?

Answer 9

yes u r clear with that?

Answer 10

Yeap!

Answer 11

to find the range(proper way) take this expression equal to some 'y' and rearrange the new eq to remove the denominator..ok?

Answer 12

So, smth like this? : 2(x-2)=x-1 and solve for x?

Answer 13

how did u het this? where is 'y'?

Answer 14

*get

Answer 15

its more like..
\[y=\frac{ x+1 }{ x-2 }\] ok? now multiply with (x-2) on both sides

Answer 16

@Zaada ??

Answer 17

oh, sorry. I was away for a min. So yes, I did multiply by (x-2) substituting y by 2.

Answer 18

hey..where is y? i don't see any 'y' on the left side..

Answer 19

\[y(x-2)=x+1\] What do I do now?

Answer 20

I see, so all real # except 1? @priyar

Answer 21

now multiply y inside..

Answer 22

and write in this form:x=..

Answer 23

x=2y+1/y-1