Question

Would some one be willing to help me with a few trig questions? Mostly just looking over my work and telling me if its right or wrong!

Answer 1

what are Q?

Answer 2

Give me a few seconds :)

Answer 3

http://prntscr.com/9rangz
http://prntscr.com/9ranke
I said D.

Answer 4

now you say that it is option D

read the step 3 where it is given that -> \(m∠SQT=180\)
if we put this value in the option D we get this->
\(m∠SQV+m∠SQT=180\)
\(m∠SQV+180=180\)
\(m∠SQV=0\)

it can be easily concluded that \(m∠SQV\) is not 0
so option D is wrong

Answer 5

Sorry I meant A x.x
I dunno why I typed D :(

Answer 6

A is correct :)

Answer 7

Mind checking a few more for me?

Answer 8

okay i can help checking :)

Answer 9

http://prntscr.com/9ratj5
I'd say B.

Answer 10

Ill be back in about 10 minutes or so...Do you mind me tagging you back?

Answer 11

feel free to tag me anytime (B

Answer 12

feel free to tag me anytime (B

Answer 13

Alright I'm back :D

Answer 14

wb :)
okay why did you say B?

Answer 15

Or would it be A?

Answer 16

is it a multiple choice question? :/

Answer 17

Yessir :)

Answer 18

:) yes now option A is correct
but look for another similar correct option

Answer 19

o.o
There is another correct one there there? I can only choose one...

Answer 20

o-o
there is for sure
it is a multiple correct answers question so you must be able to select more than 1 choices
i can prove more than 1 options correct

Answer 21

Only one choice can be selected.

Answer 22

Qwerty sire O.o

Answer 23

i am typing the proof ;-; i pressed backspace and it reloaded

Answer 24

X.X Hate when that happens D:

Answer 25

so we have this

in triangle ABC and triangle ADC
\(m∠BAC=m∠DCA~~~~~~~~~~~~~~(given)\)
\(m∠BCA=m∠DAC~~~~~~~~~~~~~~(given)\)
\(AC=AC~~~~~~~~~~~~~~~~~~~~~~\)

so both these triangles are congruent by \(ASA\) congruence
thus \(AD=BC~~~~~~~~~~~~~~(By~~~CPCT)\)

^we did this by AC=AC thing


now we will do it with DB=DB thing

in triangle DBA and triangle DBC
\(m∠ADB=m∠DBC~~~~~~~~~~~~~~(given)\)
\(m∠ABD=m∠BDC~~~~~~~~~~~~~~(given)\)
\(DB=DB~~~~~~~~~~~~~~~~~~~~~~\)

so both these triangles are congruent by \(ASA\) congruence
thus \(AD=BC~~~~~~~~~~~~~~(By~~~CPCT)\)