a trough is filled with water weighing 62.4 pounds per cubic foot and its vertical ends have the shape of the parabolic region. find the hydrostatic force on one end of the trough.

Question

zaxoanl · Answer

so F=PA  P=distance*density  
$$(x-h)^2+(y-k)^2=r^2$$
$$x=\sqrt{16-(y-4)^2}$$
$$62.4\int\limits_{0}^{4}2\sqrt{16-(y-4)^2(4-y)}dy$$

zaxoanl · Answer

not sure if i set it up correctly and how do you integrate it

irishboy123 · Answer

you're using the equation of a circle,but isn't it  parabolic?

maybe you have a link or something to share?