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can you simplify X’Y’Z + (X’Y’Z)’ ? (Boolean....)
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replace X'Y'Z with u you have u+u'=?
the + means inclusive or right? inclusive or means....
I know U+U' =1 in Boolean but how I should get there from the given equation?
you can do a truth table for u+u'
are you confused about the other operations going on?
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X’Y’Z + (X’Y’Z)’ you don't even need to look at then and stuff going on... this is equivalent to u+u' where u=X'Y'Z
ok, got it , tx
k
Though you could just look at X'Y'Z instead of replacing it with u and assume X'Y'Z is true and so (X'Y'Z)' is false so (X'Y'Z)+(X'Y'Z)' is true and then do something similar for assuming X'Y'Z is false ....
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