Question

help

Answer 1

@jhonyy9

Answer 2

how you think ?

Answer 3

it ?

Answer 4

this is a standard form of y=mx+c

do oyu know it sure - yes ?

Answer 5

you wan being there - sorry

Answer 6

1. 1=m*1 +c
2. -2 = m*2 +c
3. -5 = m*3 +c
4. -8 = m*4 +c

so from these you need to get m = ? and c= ?

Answer 7

can you solve it ?

Answer 8

im here

Answer 9

1 = m+c - multiplie by -1
-2 = 2m +c

-1=-m-c
-2=-2m+c
------------
-3 = -3m 0

m = ?

Answer 10

m = -3/(-3) = ?

Answer 11

narissa please cooperate

Answer 12

-9

Answer 13

not multiplie them - so divide like 3/3 = ?

Answer 14

1

Answer 15

yes - so than m=1 how many will be c ?

Answer 16

3

Answer 17

4

Answer 18

1=m*1 +c
2. -2 = m*2 +c
3. -5 = m*3 +c
4. -8 = m*4 +c

how you have got it please ?

Answer 19

1*4

Answer 20

substitute the m=1 in place of m inside second equation
-2 = 2*1 +c

c = ?

Answer 21

2

Answer 22

no

Answer 23

c= -4

Answer 24

soo 1,-4

Answer 25

y= x-4

prove them - try than will get these results like in table

Answer 26

so i think not will get - do you see it ?

Answer 27

1,4

Answer 28

wrong????

Answer 29

1=m*1 +c
2. -2 = m*2 +c
3. -5 = m*3 +c
4. -8 = m*4 +c

m+c=1
2m+c=-2
3m+c=-5
4m+c=-8

so the right answer m= -3 and c=4

Answer 30

thanks soooo much

Answer 31

was my pleasure

1 = m+c - multiplie by -1
-2 = 2m +c

-1=-m-c
-2=-2m+c here i have changed rigth is +2m not minus how i have wrote there - this is
------------ why i have got wrong result
-3 = -3m 0

m = ?
here above was my mistaque

sorry