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Solve x2 + 2x + 9 = 0. x equals negative 2 plus or minus 4 I square root of 2 x equals negative 2 plus or minus 2 I square root of 2 x equals negative 1 plus or minus 4 I square root of 2 x equals negative 1 plus or minus 2 I square root of 2
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\[x^2+2x+9=0\\ x^2+2x=-9\] is a start then what is half of 2?
1
ok and \{1^2=1\) so next step is \[(x+1)^2=-9+1\\ (x+1)^2=-8\]
you good from there? take the square root, get \[x+1=\pm\sqrt{-8}\] and so on
i really have no clue how to do any of this
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