Question

https://static.k12.com/bank_packages/files/media/mathml_2d66a0b057efd68489b9bd26f7082ab90a56addc_1.gif

A.
–13

B.
–4

C.
–7

D.
–16

Answer 1

\(\bf \cfrac{x-3}{2}=-5\impliedby \textit{multiply both sides by 2}
\\ \quad \\
\cancel{2}\cdot \cfrac{x-3}{\cancel{2}}=2\cdot -5\impliedby \textit{solve for x}
\)

Answer 2

HHEEELLLPPP

Answer 3

Its c. Multiply both sides by 2 x-3=-10 then add 3 to each side x=-7