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please help me step by step with this problem (4b-4a)/(ax-bx-2a+2b)
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HI!!
Hey
if there is anything to do, it must be "factor and cancel"
the numerator factors as \(4(b-a)\) which means the denominator probably has a factor of \(b-a\) in it
probably "factor by grouping" or sommat \(ax-bx=(a-b)x\) for the first part, bet you can do the second
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for the denominator i get x(a-b)-2(a-b)
so would all three (a-b) cancel?
@Qwertty123
Hello!
Hi can you help me understand? @Qwertty123
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@misty1212
Oh okay I will go through the steps then... hold on
The top is going to be different the bottom.
oh yea the top is b-a, but than the bottom would be (x-2)(a-b)
and than cancel b-a and a-b with a -1
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4b−4a _____________ ax−bx−2a+2b =?
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