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completing the square of -x^2 - 2x +3
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I got -(x+1)^2-4 but apparently its +4
how did you get -4?
\(-(x^2 + 2x+1 -4 ) \\ = -([x+1]^2 - 4) \\ = -[x+1]^2 -(-4) \\ = -(x+1)^2 +4\)
(x + a)^2 = x^2 + 2a*x + a^2 notice the relationship from 2a and a^2, that is where you take half your middle coeffiecient 1/2*[2a] = a, then square it , a^2
-x^2 - 2x +3 -( x^2 + 2x ) - 3 -------------------- 2a = 2 here
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