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Which polynomial identity will prove that 117 = 125 − 8? Difference of Squares Difference of Cubes Sum of Cubes Square of a Binomial
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@hartnn @ganeshie8
125=5^3
8=2^3
a³ - b³ = (a - b)(a² + a b + b²) 125 - 8 = 5³ - 2³ = (5 - 2)(5² + 5·2 + 2²) = 3·39 = 117
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difference of cubes ?
yup :)
difference of cubes a³ - b³ = (a - b)(a² + a b + b²) 125 - 8 = 5³ - 2³ = (5 - 2)(5² + 5·2 + 2²) = 3·39 = 117
Thank you!! :)
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