Question

what is x?

Answer 1

\[\sqrt{3x-8}+1=\sqrt{x+5}\]
@dan815 @zepdrix

Answer 2

@desmarie

Answer 3

rad 3x - 8 + 1= rad x +5
(rad 3x - 8)^2 = (rad x +5)^2 - you do this to get it out of the radical sign
3x - 8 +1 = x + 5
2x = 5 + 7
2x = 12
x = 6

Answer 4

let me know if it is right.

Answer 5

@Trisaba