Question

One Question, Help?

Answer 1

8.) Solve the system by elimination

-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Answer 2

I am no good at this elimination shat

Answer 3

me neither, that is what computer are for

Answer 4

you need a method or an answer ?

Answer 5

in this case the method is not that hard, but still ...

Answer 6

google system of 3 linear equations calculator it will come up

Answer 7

or use this
http://www.wolframalpha.com/input/?i=-2x%2B2y%2B3z%3D0%2C+-2x-y%2Bz%3D-3%2C+2x%2B3y%2B3z%3D5+

Answer 8

one approach
pick 2 equations and eliminate one variable.
pick a different set of 2 equations and eliminate the same variable you eliminated when you did the first 2 equations.
now you have 2 equations with 2 variables.
can you continue now?

Answer 9

eh

Answer 10

yes hold on

Answer 11

x = 1; y = 1; z = 0; (x, y, z) = (1, 1, 0) that is the answer?