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Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective function. x>0 y>0 y<1/3x+3 5>y+x Objective Function: C = 6x – 4y 8) substitute/eliminate x = +y +3/2z-0 substitute/eliminate y = -2/3z+1 Solution: x = 1; y = 1; z = 0; (x, y, z) = (1, 1, 0)
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