Question

Need help!!

Answer 1

Find the slope of the tangent to the curve y= x^2- x at the point (3,6).

Answer 2

f(x+h)-f(x) / h

Answer 3

f(3)^2-(3)+h) - (3)^2-(3) / h

Answer 4

(6+h)-6/ h

Answer 5

@Ella4184 @faariat

Answer 6

take the derivative

Answer 7

= (6+h)-6/h + (6-h)-6/ (6-h)-6
= 6-h+36 / h.(6-h)-6

Answer 8

@raffle_snaffle am I doing it right?

Answer 9

= (6+h)-6/h + (6-h)-6/ (6-h)-6
= 6-h+36 / h.(6-h)-6
= 6-36/ (6-h)-6
=-30/(6-h)-6
= -5/(6-h)

Answer 10

Did I make any mistake?

Answer 11

I am trying to look at what you did