In the below system, solve for y in the first equation.
x − 3y = −6
2x − 7y = 10
A. one thirdx + 2
B. negative one thirdx + 6
C. −x + 2
D. negative one thirdx + 2
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OpenStudy (bemoseemo):
just need a walkthrough or can I just this away?
OpenStudy (gabylovesyou):
Wym?
OpenStudy (gabylovesyou):
I have no idea how to do this .. Lmfao 😂
OpenStudy (nitroster):
I know how to
OpenStudy (bemoseemo):
can I say the answer?
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OpenStudy (nitroster):
stick with bemo... :P But bemo, explain it. She doesnt know it..
OpenStudy (gabylovesyou):
Can you try to explain? :)
OpenStudy (bemoseemo):
ill try to explain as well as I can
OpenStudy (gabylovesyou):
Okay thank you.
OpenStudy (bemoseemo):
so first we have x -3y,
to help find y, we also have 2x -7y
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OpenStudy (gabylovesyou):
Ok
OpenStudy (bemoseemo):
try to finish this:
x−3y=−6
(x−3y)+(−x)=−6+(−x)
x−3y−x=−6−x
OpenStudy (gabylovesyou):
3y = -6-x ?
OpenStudy (bemoseemo):
this is a screenshot of all the work explained out
OpenStudy (hamde):
x=3y-6
2(3y-6)-7y=10
6y-12-7y=10
-y-12=10
-y=22
y=-22
then
x=3*-22-6
x=-66-6
x=-72
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OpenStudy (bemoseemo):
one thirdx + 2 once you simplify it
OpenStudy (gabylovesyou):
Oh ok
OpenStudy (gabylovesyou):
And now for the other one?
OpenStudy (bemoseemo):
I have to go, but try to figure out how I worked it through in that screenshot k?