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he list below shows all of the possible outcomes for flipping four coins. HHHH HHHT HHTH HHTT HTHH HTHT HTTH HTTT THHH THHT THTH THTT TTHH TTHT TTTH TTTT What is the probability of getting the same number of heads and tails?
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So how many of them have 2H's and 2T's ? HHTT HTHT there are a few more :) count them up!
I got six
Ok good, 6 sounds right. We want a probability, so we need to divide `our 6 flips` by the `total number of flips`.
6/16?
Yay good job \c:/ Maybe simplify your fraction by cutting both numbers in half.
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thank you! c:
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