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Mathematics 7 Online
OpenStudy (anonymous):

Can anyone help me figure out what square root 50 over 0.82 is?

OpenStudy (anonymous):

I meant simplified to

jhonyy9 (jhonyy9):

sqrt50 = 5sqrt2 and rewrite 0,82=82/100 5sqrt2 5sqrt2 100 50 250sqrt2 ------ = ------- = 5sqrt2 * ------ = 5sqrt2 *------ = -------- 0,82 82 82 41 41 ------ 100

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