Question

I can medal if it means ill get help....
~
I need to understand how to add, subtract, and simplify complex fractions. If anyone could help with this, it'd be really helpful.
(b^2-2b-8/b^2+b-2) - (6/b-1)
Thanks, if anyone can help me...

Answer 1

You need to factor the first term and cancel factors and it becomes very easy.

Answer 2

(b^2-2b-8/b^2+b-2) - (6/b-1)

(b^2-2b-8) = (b-__)(b+__)

b^2+b-2) = (b-__)(b+__)

Answer 3

The final answer is (b-10)/(b-1)

It is bedtime for Bonzo. Any questions you have will have to wait until then.