Question

2.2: 1 (solving problems)

Answer 1

http://prntscr.com/9vcsnq

Answer 2

Solve y'=x^2/y (seperable)

Answer 3

dy/dx =x^2/y
y dy=x^2 dx
int y dy = x^2 dx
y^2/2=x^3/3+C

Answer 4

you forgot the int on the other side but whatever, doesn't matter lol

Answer 5

y^2=2/3 x^3+C
\(\Huge y=\pm \sqrt{2/3 x^3+C}\)
and oh whoops