HELP!! Will medal and Fan!!!!! PLEASE!!!
Joyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. She has made an error in one of the steps below. Find the step where Joyce went wrong. Step 1: x equals negative 8 plus or minus the square root of the quantity eight squared minus four times one times seven, end quantity, all over two times one. Step 2: x equals negative 8 plus or minus the square root of sixty-four minus twenty-eight all over two times one. Step 3: x equals negative 8 plus or minus the square root of thirty-six all over two times one. Step 4: x equals negative 8 plus or minus six all over two. Step 1 Step 2 Step 3 Step 4
thought it was A but its not
@NatsuOniKaze @CandyCove
@soprano.h.d0816 @pizza12
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what is that? i said it was D not A and got it wrong...
@AloneS
I believe it is Step 1
ok next one? i have 7
@airjordan200
Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. −b b2 − 4ac 2a Use the part of the quadratic formula that you chose above and find its value, given the following quadratic equation: 2x2 + 7x + 3 = 0
this is the next one...
its a fill in the number i thought it was 0 but its not
@CandyCove
@ilovehorses14
I believe it's 1
okay thanks
How can you tell when a quadratic equation has no real solutions? When the radicand is negative When b in the quadratic formula is greater than the radicand When the radicand equals zero When the radicand is not a perfect square
thought it was a but nope
@PhantomCrow
If the number under the square root is negative.
sooo before that one the other one that one was a=2 b=7 c=3
Since square roots of negative numbers cannot real numbers
ok thanks and what do you mean @PhantomCrow
so its C?
If you think about it, a square root is basically asking what two same numbers multiply to give you what is being rooted. You cannot multiply two same numbers and receive a negative number.
When the radicand is not a perfect square
It's D
okay thanks
ima o wit that to
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? x ≈ −3.23 and x ≈ 0.23 x ≈ −2.72 and x ≈ −0.28 x ≈ 0.28 and x ≈ 2.72 x ≈ −0.23 and x ≈ 3.23
It isnt D.
i thought this was a but its not
i said c
Its A
last one?
can you help me with this one?
ok
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? x ≈ −3.23 and x ≈ 0.23 x ≈ −2.72 and x ≈ −0.28 x ≈ 0.28 and x ≈ 2.72 x ≈ −0.23 and x ≈ 3.23
i reput it its not a
thats what i said and i got it wrong
@PhantomCrow u there? @airjordan200
Solve: 5x2 + 25x = 0. x = 0, x = 5 x = 0, x = −5 x = −5, x = 0, x = 5 x = 5, x = 25
what about this one?
i said a but nope
sorry im busy but i can help u
What are the exact solutions of x2 = 5x + 2? x = x equals 5 plus or minus the square root of thirty-three all over 2 x = x equals negative 5 plus or minus the square root of thirty-three all over 2 x = x equals 5 plus or minus the square root of seventeen all over 2 x = x equals negative 5 plus or minus the square root of seventeen all over 2
help me with these three please and than there is one more
@airjordan200
ok
i said all of these were a
x=-2/3
where did u get that from?
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth? x ≈ −3.23 and x ≈ 0.23 x ≈ −2.72 and x ≈ −0.28 x ≈ 0.28 and x ≈ 2.72 x ≈ −0.23 and x ≈ 3.23
Solve: 5x2 + 25x = 0. x = 0, x = 5 x = 0, x = −5 x = −5, x = 0, x = 5 x = 5, x = 25
What are the exact solutions of x2 = 5x + 2? x = x equals 5 plus or minus the square root of thirty-three all over 2 x = x equals negative 5 plus or minus the square root of thirty-three all over 2 x = x equals 5 plus or minus the square root of seventeen all over 2 x = x equals negative 5 plus or minus the square root of seventeen all over 2
Solve: 16x2 − 81 = 0. x = 4, 9 x = −4, −9 x = 9 over 4, x = −9 over 4 x = 81 over 16, x = −81 over 16
these are the last 4 please help me
help?
@sws_pvt
what does it mean when you say 16x2? Are you supposed to multiply those?
16x^2
@sws_pvt i have 4 more please
no its not its the value x
im confused
so whats goin on?
i need help with these last 4 problems...
256x-81=0 256x=81 x= 3.1604 For your last question
i give up
dont give up
(4x+9)(4x-9)=0 x= +/- (9/4) . . . 6x - 2 = x^2 0=x^2-6x+2 0=x^2-6x+9+2-9 7=(x-3)^2 +-sqrt(7)=x-3 3%2B-sqrt%287%29=x . . . 8x + 4 = 2x^2 0=2x^2-8x-4
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