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The medians of a right triangle which are drawn from the vertices of the acute angles are 5 and \(\sqrt{40}\). what is the length of the hypotenuse? Please, help
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|dw:1453934941366:dw|
\((2x)^2+y^2= 40\\ x^2+(2y)^2=25\)
so you wanna h \(h=\sqrt{4x^2+4y^2 }=\sqrt{4(9+4)}=\sqrt{52}\)
http://www.wolframalpha.com/input/?i=x%5E2%2B4y%5E2%3D25%2C4x%5E2%2By%5E2%3D40
Thank you so much, my friend.
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