Question

Some one please help!!
Solving systems using substitution

Answer 1

okay i will help u

Answer 2

X=-y+3
2x-y=0

Answer 3

This question is confusing me n i dont understand it

Answer 4

okay well lets break it down for u

Answer 5

/| x+y-3 = 0| 2*x-y = 0
We try to solve the equation: x+y-3 = 0
x+y-3 = 0 // - x-3
y = -(x-3)
y = 3-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| 2*x+x-3 = 0| y = 3-x
3*x-3 = 0 // + 3
3*x = 3 // : 3
x = 3/3
x = 1
We insert the solution into one of the initial equations of our system of equations
For y = 3-x:
y = 3-1
y = 2
We get a system of equations:
/| y = 2| x = 1