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Mathematics 19 Online
OpenStudy (shaleiah):

Check my answer?

OpenStudy (shaleiah):

I got 591.6

OpenStudy (hauntedwoodsgal):

What do I need to check?????

OpenStudy (shaleiah):

Did I solve the surface area, correctly?

OpenStudy (igigighjkl):

I might be able to help.

OpenStudy (hauntedwoodsgal):

and you got 591.6

OpenStudy (igigighjkl):

Do I do one surface or the hole thang

OpenStudy (shaleiah):

We do the whole surface area.

OpenStudy (shaleiah):

@jdoe0001

OpenStudy (jdoe0001):

yes...hmmm how did you get that area anyway?

OpenStudy (igigighjkl):

I gots 1,600?

OpenStudy (hauntedwoodsgal):

Come to think of it yeah did you use a calculator @shaleiah

OpenStudy (shaleiah):

Yeah, my ti-84 plus.

OpenStudy (jdoe0001):

is that what the teacher asked to do with it?

OpenStudy (igigighjkl):

Yes.

OpenStudy (hauntedwoodsgal):

Did the teacher tell you to use the calculator???

OpenStudy (jdoe0001):

for if that's the case, then all the credit belongs to the ti-84 pus

OpenStudy (igigighjkl):

...

OpenStudy (igigighjkl):

Y

OpenStudy (shaleiah):

\[6*\frac{ 1 }{ 2 }*18*10.4=\]

OpenStudy (hauntedwoodsgal):

Cause if you are using a calculator then that's cheating

OpenStudy (shaleiah):

Is the proper formula I enter jdoe?

OpenStudy (igigighjkl):

Who cares. :D

OpenStudy (jdoe0001):

\(\bf 6*\frac{ 1 }{ 2 }*18*10.4= \huge ?\) bacon powder? that is, what does that mean?

OpenStudy (igigighjkl):

Just kidding.

OpenStudy (jdoe0001):

anyway.... let's start off hmmm notice, you have a HEXAgonal prism hexa = 6, six sides so... notice, it has 6 rectangles, of 12x18 so get the area for those first

OpenStudy (hauntedwoodsgal):

I got 561.6 lol

OpenStudy (igigighjkl):

@dan815 @Hero @jabez177 @Kitten_is_back @EclipsedStar

OpenStudy (igigighjkl):

(panic mode)

OpenStudy (igigighjkl):

Small

OpenStudy (shaleiah):

That would equal 216

OpenStudy (hauntedwoodsgal):

I believe that's right

OpenStudy (jdoe0001):

216?

OpenStudy (jdoe0001):

ohhh hmm yes that's one rectangular face though notice, there are 6 of them, so add them up

OpenStudy (hauntedwoodsgal):

Yes I believe that is correct??

OpenStudy (hauntedwoodsgal):

Hmm

OpenStudy (shaleiah):

1296

OpenStudy (hauntedwoodsgal):

Mhm

OpenStudy (jdoe0001):

after you get those get the area of the 2 regular hexagonal faces keeping in mind that \(\bf \textit{area of a regular polygon}=\cfrac{1}{2}\cdot rns\qquad \begin{cases} r=apothem\\ n=\textit{number of sides}\\ s=\textit{length of each side} \end{cases}\) notice, those are 2 hexagonal faces then sum those two up with the other 6 and that'd be the total surface area of the figure

OpenStudy (jdoe0001):

the "apotem", is the distance, from one side, to the center of the regular polygon in this case, the 10.4 distance

OpenStudy (hauntedwoodsgal):

Ok so are you good???

OpenStudy (shaleiah):

I don't think I got the correct value...6739.2

OpenStudy (hauntedwoodsgal):

Hmm I got 561.6

OpenStudy (hauntedwoodsgal):

So you don't need anymore help @shaleiah

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