Please can someone help me solve this i will appreciate it! Evaluate the function below for x=2 F(x)=x^4+6x^3+3 A.55 B.47 C.59 D.67
put 2 in place of x everywhere...
@lovelyyvaal ?
so F(2)=?
\[F(2)=2^{2}+6\times2^{3}+3\] I think that's how it's supposed to look
I don't know about "F(2)" though I know it's called "Function Notion" or something like that ,but unsure
yea thats how i set it up @LoveIt
@priyar
@zepdrix
its 2^4 (first term)
coz there is x^4.. the rest of it is perfect!
then just evaluate..you will get the answer..1
summary: if y = x^4, and x = 2, then y = (2)^4 = 2 * 2 * 2 * 2 = ?
@mathmale 16?
\[F(2) = 2^{4} + 6(2^{3}) +3\] \[F(2) = 16 + 48 + 3\] \[F(2) = 67\]
Yes, 2^4=16.
Really? How's your synthetic division? MUCH easier.
i have so far 4+6(2)^3+3 did i set it up right?
Even more "Really?!" Why are we doing your quiz for you? Close it and do your own examination, please.
@tkhunny just wanted for someone to help me out step by step so i can write down how it was solved and do it myself when i get another question thats how i learn but sorry this offends you !
"Evaluate the function below for x=2 F(x)=x^4+6x^3+3" Method 1: Replace each incidence of "x" in the function F(x) with (2): F(2)=(2)^4+6(2)^3 + 3. Can you evaluate that? If not, about what are you uncertain regarding what to do? Method 2: Use synthetic division (provided that you already have experience with it): F(x)=x^4+6x^3+3 becomes \[F(x)=1x^4+6x^3+0x^2+0x +3,\]
so the coefficients of F(x) are, in order, 1 6 0 0 3. Use the divisor 2. If you've already learned synth. div., great. If not, and you have time, someone else or I could introduce the procedure. You'd want to divide by 2: 2 / 1 6 0 0 3 Otherwise Method I will work all right. Review this entire conversation, looking for the value of 2^4. Next, calculate 2^3 and multiply the result by the coefficient 6. Form your final result by adding up the values of 2^4, 6(2)^3 and the constant, 3. Questions?
What part about this being a graded quiz are you not understanding? You should pay more to get people to help you cheat. We do not want to be in that business.
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