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Mathematics 20 Online
OpenStudy (anonymous):

Check My Work? #Medal&Fan !!

OpenStudy (anonymous):

@Astrophysics Am I correct?

OpenStudy (astrophysics):

Almost, one more step \[\log_a(a) = 1\]

OpenStudy (anonymous):

Ok so that would be the final answer. Thanks I appreciate it.

OpenStudy (astrophysics):

Not quite, \[-2\log_6(6) \implies -2 (1) = -2\]

OpenStudy (astrophysics):

Use the rule to make that 1, then -2 is your final answer

OpenStudy (astrophysics):

Yeah :)

OpenStudy (anonymous):

Thank you, I appreciate the help!

OpenStudy (astrophysics):

Yw

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