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Mathematics 14 Online
OpenStudy (calculusxy):

Solve for the side of the following right triangle.

OpenStudy (calculusxy):

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OpenStudy (calculusxy):

I know the ratios are 30 - 60 - 90 x - x\(\sqrt{3}\) - 2x so i would find x (opposite of 30°) first. 4 = x\(\sqrt{3}\) \(\large \frac{4}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{4\sqrt{3}}{3}\)

OpenStudy (calculusxy):

x = \(\large \frac{4\sqrt{3}}{3}\)

OpenStudy (calculusxy):

y = \(\large \frac{8\sqrt{3}}{3}\) am i correct?

OpenStudy (calculusxy):

@ParthKohli

OpenStudy (calculusxy):

@AravindG Can you please check?

OpenStudy (calculusxy):

I am in prep for a test tomorrow.

OpenStudy (aravindg):

You are right. Further you can simlify 8sqrt(3)/3 as 8/sqrt(3)

OpenStudy (calculusxy):

why?

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