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Mathematics
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Solve for the side of the following right triangle.
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|dw:1454039443757:dw|
I know the ratios are 30 - 60 - 90 x - x\(\sqrt{3}\) - 2x so i would find x (opposite of 30°) first. 4 = x\(\sqrt{3}\) \(\large \frac{4}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{4\sqrt{3}}{3}\)
x = \(\large \frac{4\sqrt{3}}{3}\)
y = \(\large \frac{8\sqrt{3}}{3}\) am i correct?
@ParthKohli
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@AravindG Can you please check?
I am in prep for a test tomorrow.
You are right. Further you can simlify 8sqrt(3)/3 as 8/sqrt(3)
why?
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