Question

tell between which 2 consecutive integers the square root of 67 lie

Answer 1

Well lets start off with \[\sqrt{67}\] what do we get?

Answer 2

\(1^{2} = 1\)
\(2^{2} = 4\)
\(3^{2} = 9\)
\(4^{2} = 16\)
\(5^{2} = 25\)
\(6^{2} = 26\)
\(7^{2} = 49\)
\(8^{2} = 64\)
FOUND IT! It's in here, somewhere. No need to calculate it's value. Just answer the question.
\(9^{2} = 81\)

Answer 3

I think I got it. The square root of 67 lies between 8 and 9?

Answer 4

@tkhunny 6^2 =36 - not 26 - sorry for my attention

Answer 5

I'm delighted that you actually read it.