Question

An object is at the end of a spring at the bottom of the ramp.The spring is stretched 2.5 cm.What is the horizontal range of the object? k=1500 N/m,incline =30 degrees)

Answer 1

do u have a diagram that goes with this?

Answer 2

@iceman60 ?

Answer 3

This is what I madee. http://imgur.com/kmIHk7e .No diagram is available

Answer 4

Hint:
on the object are acting two forces:
1) the force due to gravity, whose magnitude is \(mg \sin \theta\) where \(\theta =30\) degrees
2) the eleastic force, whose magnitude is \(K \delta\), where \(\delta =2.5 \cdot 10^{-2}\) meters
so, at equilibrium, we have:
\[\Large mg\sin \theta = K\delta \]
And the horizontal range is gi:
\(\Large 2 \delta \cos \theta\)