Question

Simplify sec x-tanx sinx

Answer 1

I have gotten to (1-sinx^2)/cosx but I don't know how to proceed

Answer 2

\[\frac{ 1 }{ \cos x }-\frac{ \sin x }{ \cos x }*\sin x=\frac{ 1-\sin ^2x }{ \cos x }=\frac{ \cos ^2x }{ \cos x }=\cos x\]

Answer 3

Thank you very much!