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What is the equation of a line that passes through (7,8) and has a slope of -3?
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\(\sf\Large y-y_1=m(x-x_1)\) Where \(\sf\Large (x_1,y_1)\) is the point, and \(\Large\sf m\) is the slope
Welcome to OpenStudy! @K.H Can you post the answer choices? :)
y=-3x+29 y=3x+13y y=1/3x - 29 y=-1/3x - 13
so for point slope youd have y-8=-3(x-7)
Now you distribute the negative 3. Hint: a(b-c) = ab - ac so what is -3(x-7) = ??
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Answer is 1st. Option
Answer is 1st. Option
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