Trigonomatry Question
Questions is in the pictures :)
Hey @Ahsome, what do you think?
I would say this question can be done without any knowledge of trigonometry using similarity of triangles.
I thought similar triangles play a role, but I cant seem to find any way to solve. We are notigen \(h\), and I don't know how to get that value. We do need \(h\) right?
But we can find \(h\) by using similar triangles, yeah. The small right triangle that is orange in colour has sides \(h\) and \(R-r\), and they correspond to \(H \) and \(R\) in the bigger triangle.\[\frac{h}{R-r}=\frac{H}R\]\[h = H \cdot \frac{R-r}{R}\]
So your answer is simply\[V(r)=\frac{\pi r^2 H(R-r)}{R}\]
Thank you so much! I completely forgot about how similar triangles work, you have been immensely helpful
No problem =)
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