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I think they want you to plot the curve, and then "find the area under the curve" (area will be equal to the integral)
I realized that, I just got stuck at graphing it.
Could you help me graph it? I can do the rest
y=5 is a horizontal line (show this from x=0 to x=5) y= -x+10 is the equation of a line with slope -1 plot two points (say at x=5 and at x=10, and "connect the dots")
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you should get a square and a triangle
Isn't it easier to integrate both definite integals and evaluate over 0 to 5 plus 5 to 10 ? Which is essentially the same thing.
Is this right?
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