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MULTIPLE CORRECT QUESTION
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Considering the equation \(\large \bf \frac{2}{x}+\frac{5}{y}=\frac{1}{3}\),\(\large \bf ~where~x,y \in N\). The number of solution of the equation is :- A) 6,if both x and y are even B) ,if both x and y are odd C) 0,if x is even whereas y is odd D) 0,if x is odd whereas y is even
either a or b
\[6y + 15x = xy\]\[\Rightarrow xy - 15x - 6y = 0\]\[\Rightarrow xy - 15x - 6y + 90= 90\]\[\Rightarrow x(y-15) - 6(y-15) = 90\]\[\Rightarrow (x-6)(y-15)=90\]
then
Now factorise \(90\) and see the solutions.
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\[\large \bf (x-6)(y-15)=2 \times 3^2 \times 5\]
If x-6=2 i.e even then x=8, y-15=45
Yup, that's how you solve it.
thank you parth :)
np
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