MEDAL FOR YOU? Please help.
Help with what?
If it's reflected across the 'Y' axis, just change the 'x' values to the opposite of what they are :)
oh so it is D? P'(-2,4),Q'(5,-3),R'(1,2)
No, it would be C. D is making both values (X, Y) opposite of what they are which wouldn't be correct. You're just making the (X, ) value opposite.
oh I see. THank you for clarifying
can you try this one?
Oh I love problems like that! Okay so if you look at it, AE is the same size as ED which means AD is 2 times the size of AE/ED. So that would mean that BE is 1/2 of CD so if you take 3x = 1/2(48) what would you get?
24 8
That looks correct to me :)
thank you do you like these?
For seven since the sides are the same size, that means the bottom two angles will be congruent which means that if you do 180-48 to get 132 and divide that by 2 to get 66 that means 66 is the size for each angle on the bottom.
For 8 the Transitive property of equality says that if A=B and B=C then A=C basically. So take a look at the answer choices for 8 and see which one fits that rule.
thanks are you saying that 13x 11, 3, 6 or 12 minus 2 is suppose to equal 39? im confused.
For which question?
I didn't even see the second part on question8, one sec
Number 30 I explained above, for number 31, the angles will all add up to 360, so if you do 360-2(39) you'll get 282. Now you want to setup 2(13x-2)=282 and solve that to get X.
Thank you YOu are medaling yourself. I would do it for you!
Can you help with these 3?
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