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Find f[g(x)] if f(x) = x^4 + 1 and g(x) = x^2.
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I got x^8+1
Yes, correct:)
\(\color{#000000 }{ \displaystyle f(\color{red}{x})=\color{red}{x}^4+1 }\) \(\color{#000000 }{ \displaystyle f[\color{red}{g(x)}]=\left(\color{red}{x^2}\right)^4+1 }\) \(\color{#000000 }{ \displaystyle f[g(x)]=x^{2\times 4}+1 =x^8+1 }\)
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