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@soprano.h.d0816
So, it starts out at 25 mi and at exactly 1 hour it is 75 mi So, subtract 25 from 75 and you get your answer(:
as we can see from the graph, the line passes at points \((0,25)\) and \((4,225)\), so the speed, being the slope of such line, is given by the subsequent computation: \[\Large s = \frac{{225 - 25}}{{4 - 0}} = ...?\]
Thank You Guys So Much For Helping Me <33 And @soprano.h.d0816 Check Your Messages For A Personal Thanks <33
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No problem hun<33
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