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Mathematics 17 Online
OpenStudy (dschneider2016):

Please Help!! Find focal width of parabola -1/40 x^2=y

OpenStudy (dschneider2016):

@zepdrix is 160 right?

OpenStudy (dschneider2016):

@rebeccaxhawaii

OpenStudy (dschneider2016):

@Zeronknight

OpenStudy (welshfella):

Hint:- the focus for x^2 = 4ay is at (0.a)

OpenStudy (welshfella):

this will be at (0, -something)

OpenStudy (dschneider2016):

um would the answer be 40? @welshfella

OpenStudy (dschneider2016):

@IrishBoy123

OpenStudy (dschneider2016):

@AihberKhan please help!

OpenStudy (welshfella):

the focuse is found by solving 4a = -40 a = -10 focus is at (0,-10)

OpenStudy (welshfella):

i cant remember what the focal width is, to be honest

OpenStudy (dschneider2016):

oh yeah me either! Im stuck between it being 40 or 160

OpenStudy (dschneider2016):

@zepdrix pleaswe check my answer?

OpenStudy (welshfella):

is the focal width 4 * 10?

OpenStudy (welshfella):

looks that way

OpenStudy (dschneider2016):

@tkhunny is it 40?

OpenStudy (dschneider2016):

@radar is it 40?

OpenStudy (tkhunny):

|4a| = 40 -- Done. Why are we still asking? Is there lingering doubt?

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