Question

I could really use some help.
81^x=27^(x+2)
I know the base is 3.

Answer 1

\[(81)^x = (3^4)^x=3^{4x}\] and \[ 27^{(x+2)}=(3^3)^{(x+2)}=3^{3(x+2)}.\]

Equating the two gives \[ 3^{4x}=3^{3(x+2)}\implies 4x=3(x+2)\implies 4x = 3x+6 \implies \boxed{x = 6}\]

Answer 2

Thank you so much @SaiyanSparta

Answer 3

Could you help me with one more?

Answer 4

Go ahead and post it. :)