A rocket is fired at an angle from the top of a tower of height h0 = 68.6 m . Because of the design of the engines, its position coordinates are of the form x(t)=A+Bt2 and y(t)=C+Dt3, where A, B, C , and D are constants. Furthermore, the acceleration of the rocket 1.10 s after firing is
a⃗ =( 2.30 i^+ 2.20 j^)m/s2.
Take the origin of coordinates to be at the base of the tower.
1.Find the constant of A
2. Find the constant of B
3. Find the constant of C
4. Find the constant of D
5. At the instant after the rocket is fired, what is its acceleration vector?

Question

A rocket is fired at an angle from the top of a tower of height h0 = 68.6 m . Because of the design of the engines, its position coordinates are of the form x(t)=A+Bt2 and y(t)=C+Dt3, where A, B, C , and D are constants. Furthermore, the acceleration of the rocket 1.10 s after firing is 
a⃗ =( 2.30 i^+ 2.20 j^)m/s2. 
Take the origin of coordinates to be at the base of the tower.
1.Find the constant of A
2. Find the constant of B
3. Find the constant of C
4. Find the constant of D
5. At the instant after the rocket is fired, what is its acceleration vector?

anonymous · Answer

6. At the instant after the rocket is fired, what is its velocity?