Question

evaluate √x+7 when x = 9.
write the answer in simplified radical form
10

16

4

8

Answer 1

@mathmale

Answer 2

Hey there!

Answer 3

hello

Answer 4

Is it the square root of x or the square root of (x + 7) ?

Answer 5

the square root of (x + 7)

Answer 6

i think the answer is 4

Answer 7

Ok, great!

So, first of all, we need to plug in x = 9

What is 9 + 7 = ?

Answer 8

16

Answer 9

And so we have:

sqrt(9 + 7) = sqrt (16) = ?

What is the square root of 16?

Hint: What times itself will give you 16?

Answer 10

4 x 4

Answer 11

So sqrt (16) = 4

Are all of the answer choices under square roots or no?

Answer 12

wait sorry i didnt get your question?

Answer 13

Are all of those numbers in your answer choices under a \(\sqrt{}\)? Or are the answers choices just a number like 4?

Answer 14

there just numbers like 4

Answer 15

Then your answer is just 4. :)

Answer 16

thanks! can you help me with 1 more question

Answer 17

Sure!

Answer 18

evaluate √24 - x when x = 6.
write the answer in simplified radical form.

√2

3

3√2

9

Answer 19

i think it's 9 because 9 cant be simplified

Answer 20

So is it sqrt (24 - x) ?

Answer 21

yep

Answer 22

What is 24 - 6 = ?

Answer 23

18

Answer 24

Now we need to simplify sqrt 18.

sqrt 18 = sqrt (9 * 2) = sqrt(9) * sqrt (2)

What is sqrt 9 = ?

Answer 25

2?

Answer 26

Does 2 * 2 = 9?

Answer 27

no 3 * 3 does so the sqrt of 9 is 3

Answer 28

Yes, so now we have

sqrt(9) * sqrt (2) = 3 * sqrt (2) = 3sqrt(2)

Answer 29

Do you understand how I simplified square root 18?

Answer 30

yes i do thanks

Answer 31

one more question? please :(

Answer 32

It was my pleasure. :)

Answer 33

Sure!

Answer 34

yay!

Answer 35

evaluate √16 - x when x = 8.
write the answer as a decimal

4

1.41

2

2.83

Answer 36

round to the nearest hundreds if necessary**

Answer 37

i think its D

Answer 38

sqrt (16 - x), right?

The parenthesis make a big difference.

Answer 39

yes

Answer 40

It is D. You are correct. :)

Answer 41

yay thanks for your help!

Answer 42

I'm glad that I was able to be of some help. :)