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@wolf1728
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The sine of 45 degrees = (sq root of 2)/2 The sine of 45 degrees = (5*sq root(2)/2)/u Therefore, (sq root of 2)/2 = (5*sq root(2)/2)/u u= (5*sq root(2)/2)/ (sq root of 2)/2 u = 5 It's an isosceles triangle so side v = other side = (5*sq root(2)/2) So, the answer is C
Thank you!
Could you help me with one more question? I think I solved it properly.
I think it's C
@wolf1728
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Yes it looks like C x = sq root (8) x = 2 * sq root (2) y=2 (it's an isosceles triangle)
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